Question

ABCD is a square of side 6 cm. F is a point on BC such that the area of the triangle ABF is one- third of the area of the square. find the length of FC​

Answer 1

Refer to the above image

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Answer 2

answer:

FC=2cm

Step-by-step explanation:

area of square=6*6=36cm²

area of triangle=1/3(area of square)

area of triangle=1/3(36)

1/2(base*height)=12

1/2(BF*AB)=12

BF*AB=24

BF=24/AB

BF=24/6

BF=4cm

Now, FC=BC-BF

=6-4

=2cm