ABCD is a square of side 6 cm. Find the area of shaded region. (√3=1.73).
Answers
Answer:
ABCD is a square of side 6cm. Find the
area of shaded region. See the image
ABCD is a square with side = 6
Area of ABCD = 6 * 6 = 36 cm²
Radius of Arc = 6 cm
Area of BAC arc = (90/ 360arc) π(6) ²= (1/4)(3.14) * 36 = 28.26 cm²
Area of ABD arc (90/360) π(6)2
= (1/4)(3.14) * 36 = 28.26 cm²
Let say intersection point of arc =P
Lets draw two straight line AP & BP = 6
cm = radius
Area of Arc APB = (60/360) * 3.14 * 62 =
18.84 cm²
Area of Arc BAP = (60/360) * 3.14 * 6? =
18.84 cm²
Area of A APB = (13/4) * 62 = 15.58
cm²
Area of Portion x = Area of Arc APB +
Area of Arc BAP - Area of triangleAPB
Area of Portion x = 18.84+18.84-25.88=22.1 cm2
Area of Shaded region = Area of BAC
arc+ Area of ABD arc - 2*Area of
Portion x
=> Area of Shaded region = 28.26 +
28.26 - 2*(22.1)
=> Area of Shaded region = 56.52 -
44.2
=Area of Shaded region = 12.32 cm²
Answer:
Answer given above in image
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