Question

ABCD is a square of side 6 cm find the length of the diagonal​

Answer 1

$\bf{\underline{\underline{Question:-}}}$

• ABCD is a square of side 6 cm find the length of the diagonal

$\bf{\underline{\underline{Given:-}}}$

• ABCD is a square of side 6cm.

$\bf{\underline{\underline{Solution:-}}}$

$\bf{\underline{\underline{By\: Pythagoras:Thereom:-}}}$

$\sf → AB^2 + BC^2 = AC^2$

$\sf → 6^2 + 6^2 = AC^2$

$\sf → 36 +36 =AC^2$

$\sf→ \sqrt{72}=AC$

$\sf → 6\sqrt{2}= AC$

$\bf{\underline{\underline{Hence:-}}}$

• The diagonal of square is 6√2 cm

Answer 2

Answer:

$\boxed{\bf 6\sqrt{2} \ cm}$

Step-by-step explanation:

$\text{side of the square,a = 6 cm} \\\\ \text{In right angled triangle,} \\ hyp^2=side_1^2+side_2^2 \\hyp^2=a^2+a^2\\hyp^2=2a^2\\hyp=\sqrt{2a^2}\\hyp=\sqrt{2} \ a \\ length \ of \ diagonal \ of \ square=\sqrt{2} a \\\\ => \sqrt{2} (6) \\\\ =>6\sqrt{2} \ cm$