Question

ABCD is a square of side a. A
body starts from A and reaches C
through the indicated path. The
ratio of displacement to distance
travelled is :
(a) 20 6 12
(6)
(d) a
V2​

Answer 1

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Answer 2

Answer:

Ratio of displacement to distance travelled is    $\frac{1}{\sqrt{2}}$

 

Explanation:

The numerical ratio of displacement to distance is  equal to or >1.

Here the displacement is either = or > than distance.

Square side is ABCD

In motion  the distance covered is the same as the displacement.

Displacement = $\sqrt{a^{2}+a^{2}}$ = $\sqrt{2} a$

Distance= 2a

$\frac{Dispalcement}{Distance}$ = $\frac{\sqrt{2}a }{2a}$

The ratio of displacement to distance travelled is $\frac{1}{\sqrt{2}}$