ABCD is a square.P and Q are points on DC and BC respectively, such that AP=DQ . Prove that ∆ADP=~ ∆DCQ .
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Given:ABCD is a square.P and Q are points on DC and BC respectively,such that AP=DQ.∆ADP=~∆DCQ
RTP:∆ADP=~∆DCQ
Proof:In ADP and DCQ
AP=DQ
<ADC=<DCQ(90°)
AD=DC
by SAS rule
ADP is congruent to DCQ
<DAP=<CDQ
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