Math, asked by OsasJ1377, 1 year ago

Abcd is a square pqrs is a rhombus lying inside the square such that p, q, r and s are the mid-points of ab, bc, cd and da respectively. a point is selected at random in the square. find the probability that lies in the rhombus
a.1/3
b. 2/3
c. 1/2
d. 1/4

Answers

Answered by enyo
12

Suppose, the side of the square ABCD is a.

Now, since the rhombus lying inside is made by the mid-points of AB, BC, CD and DA, the diagonals of the rhombus will be equal to the sides of the square i.e. a

Area of the square=a^2 and

Area of the rhombus=1/2 X product of diagonals=(1/2)a^2

Hence,  

The probability of selected point to lie inside the rhombus= area of rhombus/area of square

=1/2

Therefore, option c is correct i.e. 1/2


Answered by assasinate
4

Answer:

1/2

Step-by-step explanation:

Suppose, the side of the square ABCD is a.


Now, since the rhombus lying inside is made by the mid-points of AB, BC, CD and DA, the diagonals of the rhombus will be equal to the sides of the square i.e. a


Area of the square=a^2 and


Area of the rhombus=1/2 X product of diagonals=(1/2)a^2


Hence,  


The probability of selected point to lie inside the rhombus= area of rhombus/area of square


=1/2


Therefore, option c is correct i.e. 1/2




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