Question

ABCD is a square,prove that AC =2AB

Answer 1

Here is the answer.... Hope it helps...

Answer 2

ABCD is a square and AC is the diagonal.
So, ACD and ABC are the two right angled triangle.
Now,
In ABC, according to Pythagoras theorem .
AC sq. = AB sq. + BC sq.
but, AB = BC ( since all sides of a square area equal)
so,
AC sq. = AB sq. + AB sq.
= 2AB sq.
therefore ,
AC = 2AB.

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