Question

ABCD is a square where AB= 6. Mursalin chooses a point X inside the square such that the perpendicular distances from X to BC and CD are 2 and 3 respectively. Find the length of AX.​

Answer 1

Answer:

Let the side of square be a

BF=

2

a

and BE=

3

a

(given)

⇒ Area of triangle FBE =

2

1

×FB×BE

⇒108=

2

1

×

2

a

×

3

a

⇒a

2

=1296 cm

⇒a=36 cm

⇒AC=

2

a=36

2

cm