Question

ABCD is a square whose side is ‘a’ taking AB and AD as axes, prove that the equation of the

circle circumscribing the square is x2 + y2-a (x + y) = 0. ​

Answer 1

Answer:

ABCD is a square whose side is ‘a’ taking AB and AD as axes, prove that the equation of the

circle circumscribing the square is x2 + y2-a (x + y) = 0.

Answer 2

Step-by-step explanation:

see this attachment.....