Question

ABCD is a square. With centres B and C and radius
equal to the side of the square, circles are drawn to
cut one another at E inside the square. ZBDE is
equal to
(1) 22
(2) 30°
(3) 150
(4) 37°​

Answer 1

Given :

Square = ABCD

Centres = B and C

Circles are drawn to cut one another at = E

To find :

∠BDE

Solution:

Let the side of square be = x

Therefore,

BC = BE = CE  = x

In an equilateral triangle

∠BCD = 90°  ( Square angle)

∠BCE = 60°

∠ECD = 90° - 60° = 30°

Since, CE = CD  = x

Thus, ΔECD is an isosceles triangle

∠CDE =  ∠CED

∠CDE + ∠CED + ∠ECD = 180°

2∠CDE  + 30° = 180°

2∠CDE  = 180° - 30°

2∠CDE = 150°

∠CDE = 75°

∠CDB = 45°   ( Diagonal = BD)

∠BDE = ∠CDE  - ∠CDB

∠BDE = 75° - 45°

∠BDE = 30°  

Answer: Thus ∠BDE is equal to 30°

Answer 2

Answer:

hi

Step-by-step explanation:

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