ABCD is a square. With centres B and C and radius equal to the side of the square, circle are drawn to cut one another at E inside the square. ∠ BDE is equal to
a.22
b.30
c.15
d.37
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Answer:
⇒ In square ABCD, side of square = 5cm.
⇒ Let a=5cm.
⇒ Perimeter of ABCD = 4×a
⇒ Perimeter of ABCD = 4×5
∴ Perimeter of square ABCD = 20cm. ---- ( 1 )
⇒ Area of square ABCD = a
2
⇒ Area of square ABCD = 5
2
∴ Area of square ABCD = 25cm
2
. ----- ( 2 )
⇒ In square PQRS,
⇒ Perimeter of square PQRS = 40cm [Given] --- ( 3 )
⇒ Perimeter of square PQRS = 4×b
⇒ 40=4×a [From ( 3 )]
∴ b=10cm
⇒ Area of square PQRS = b
2
∴ Area of square PQRS = 100cm
2
------ ( 4 )
From ( 1 ) and ( 3 ) we get,
⇒
per(PQRS)
per(ABCD)
=
40
20
=
2
1
From ( 2 ) and ( 4 ) we get,
⇒
Ar(PQRS)
Ar(ABCD)
=
100
25
=
4
1
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