Question

ABCD is a square with each side 12 cm. Pisa
mensions of each
point on BC such that area of ∆ABP : area of
trapezium APCD = 1:5. Find the length of CP.​

Answer 1

Answer:

8 cm

Step-by-step explanation:

Given side of square 12 cm

Then area of square = 12×12=144 cm

2

Given the area of triangle ABP : area of trapezium APCD =1:5

Then the area of triangle ABP =

6

144

=24cm

2

Let the length of CP is x

Then area of trapezium APCD = 12×

2

12+x

=6(12+x) cm

2

But as per question area of triangle ABP : area of trapezium APCD = 1:5

Then

6(12+x)

24

=

5

1

6(12+x)=24×5=120

Or 6(12+x)=120

Or 72+6x=120

Or 6x=120−72=48

Or x=8 cm