ABCD is a square with one vertex at the center of the circle and two vertices on the circle what is the length of AC if the area of the circle is 616cm/sq
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area of circle = 616
● πr^2 =616
r^2 = 616×7/22
r^2 = 28×7
r^2 = 7×4×7
r^2 = 7^2×2^2
r =7×2 =14 cm
radius of circle = side of square
thus side square = 14 cm
length of diagonal AC = √2 × length of side of square =√2 ×14 =14√2
● πr^2 =616
r^2 = 616×7/22
r^2 = 28×7
r^2 = 7×4×7
r^2 = 7^2×2^2
r =7×2 =14 cm
radius of circle = side of square
thus side square = 14 cm
length of diagonal AC = √2 × length of side of square =√2 ×14 =14√2
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