Question

abcd is a square with side a unit with centres a,b,c and d four circles are drawn such that each circle touches externally two if the remaining three circles. the area enclosed by the square and exterior of circle is​

Answer 1

Answer:

Step-by-step explanation:

Answers

debtwenty12pe7hvl

Debtwenty12pe7hvlAce

Where is the figure and which part is shaded ,inside the square or outside the square or space between the circles? probably it will be the space between the circles in side the square. if so

Side of square = 14 cm

Four quadrants are included in the four sides of the square.

∴ Radius of the circles = 14/2 cm = 7 cm

Area of the square ABCD = [side]^2 =14^2 = 196 cm2

Area of the quadrant = (π R^2)/4 cm^2 = (22/7 × 72)/4 cm^2

= 77/2 cm^2

Total area of the quadrant = 4 × 77/2 cm^2 = 154 cm^2

Area of the shaded region = [Area of the square ABCD - Area of the quadrant]

= 196 cm^2 - 154 cm^

= 42 cm^2 ANS

Answer 2

Answer:

42 cm²

Step-by-step explanation:

I have attached the answer. Here I will give you the explanation!

First is entry the given values under appropriate headings, so it will be easy for you.

Next the value of radius is not given, but the question says that the side of square is equal to 14 cm & they gave the circles touch externally on the side of square. So the value of radius is 7cm.

Then they asked the area of shaded one.

So you need to subtract the area of quadrant from the area of square.

And you need to substitute the values given in the beginning down.

If the question gives you the value of pi then use it, otherwise you 22/7

Then calculate as given in the attachment you will get the answer as 42 cm².

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