Question

ABCD is a square. X is any point on BD. AX and CX are joined. Is AX=CX? Give reasons?

Answer 1

Answer:

hope this is the method...

Answer 2

Proved AX = CX

•As we know ABCD is a square .

AB = CD ( side of same square)

also , AB || CD

•In triangle BAX and triangle DCX

AB = CD ( sides of same square) <BAX = <DCX ( Alternate interior <ABX = <CDX angles)

•triangle BAX is congruent to triangle DCX

By AAS criterion

•AX = CX ( CPCT)

hence proved