Question

ABCD is a straight line with AB= BC = CD. P is a point not on the straight line such that PB = PC prove that PA = PD

Answer 1

Answer:

Draw a line ABCD

Such that       AB = BC= CD

Taking Point P and joining with Points B and C

it is given that     PB = PC

Now in Triangle ABP and DPC

AB = CD

PB = PC

and

Angle PBA = Angle PCD

Thus by SAS

Triangle are similar

PA = PD

Hence Proved

Step-by-step explanation:

Answer 2

Answer:

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