ABCD is a string suspended from points A and D and it carries a weight 20 kg at B and a
weight W kg at C. The portion AB is horizontal and BC and CD make angles of 60° and 30°
with the vertical. Find W and the tensions in the three portions of the string.
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First string ABCD is split in to two parts, and consider the joints B and C separately Let, T1 = Tension in String AB.
T2 = Tension in String BC
T3 = Tension in String CD
Since at joint B there are three forces are acting.
SO Apply lamis theorem at joint B,
T1/sin 60° = T2/sin 150° = 1000/sin 150°
T1 = {sin 60° × 1000}/sin 150°
= 1732 N
T2 = {sin150° × 1000}/sin 150°
= 1000N
Again Apply lamis theorem at joint C,
T2/sin 120° = T3/sin 120° = 1000/sin 120°
T3 = {sin 120° × 1000}/sin 120°
= 1000N
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