ABCD is a traingle.AB=10cm, BC=6cm.then ,what is the area of the rectangle? and what is the area of triangleAPB?
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Answer:
In Given Triangle ABC
AC2+ AB2 = BC2
(6*6)+(8*8)= BC2
BC2=64+36
BC2=100
BC=10
Area of Triangle ABC= 8*6/2
=24 Cm2
Semiperemetre of ABC= (8+6+10)/2
=12 cm
Radius of circle= Area Of Triangle /Semiperimeter of triangle
= 24/12
= 2 cm
Hence Radius of circle is 2 cm
hope it became easy to understand by the diagram...
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