ABCD is a trapeIum ABII CD angle a = angle b = 40 degres, find angle c and d are the equal?
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Given
- ABCD is a trapezium,
- AB║CD
- ∠A = ∠B = 40°
To find
- ∠C and ∠D
Solution
- ∠A = ∠B = 40°
- ∠B + ∠C = 180° (Adjacent angles are supplementary)
- 40° + ∠C = 180°
- ∠C = 180° - 40°
- ∠C = 140°
☯ Measure of ∠C = 180°
- ∠A + ∠D = 180° (Adjacent angles are supplementary)
- 40° + ∠D = 180°
- ∠D = 180° - 40°
- ∠D = 140°
☯ Measure of ∠D = 140°
✯ ∠C = ∠D = 140° ( ∴ They are equal )
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