Question

ABCD is a trapeium in which AB parallel to DC and area of triangle AOB=108cm2 area of triangle COD is​

Answer 1

Answer:

Given that.

AB II CD

In Δ AOB and Δ COD

∠OAB = ∠OCD (Alternate interior angles)

∠OBA = ∠ODC (Alternate interior angles)

∠AOB = ∠DOC (Vertically opposite angles)

ΔAOB ~ ΔCOD (AAA similarly)

We know that,

area of triangle AOB = area of triangle COD = 108 cm^2