Math, asked by rananya661, 2 months ago

ABCD is a trapeium in which AB parallel to DC and area of triangle AOB=108cm2 area of triangle COD is​

Answers

Answered by Madhav4244
2

Answer:

Given that.

AB II CD

In Δ AOB and Δ COD

∠OAB = ∠OCD (Alternate interior angles)

∠OBA = ∠ODC (Alternate interior angles)

∠AOB = ∠DOC (Vertically opposite angles)

ΔAOB ~ ΔCOD (AAA similarly)

We know that,

area of triangle AOB = area of triangle COD = 108 cm^2

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