Question

ABCD IS a trapezium AB 7BC 12 FIND fc​

Answer 1

The length of FC = 25.875

Step-by-step explanation:

Given data AB = 7 = ED

BC = AF = 12

In Δ AEF

$\cos 45$ = $\frac{EF}{AF}$

EF = 12 × $\cos 45$

EF =  8.485

In Δ BCD

$\sin 60$ = $\frac{CD}{12}$

CD = 12 × $\sin 60$

CD = 10.39

Thus FC = FE + ED + DC

Put all the values in given formula

⇒ FC = 8.485 + 7 + 10.39

⇒  FC = 25.875

Therefore the length of FC = 25.875