Question

ABCD is a trapezium AB || DC, P and Q are midpoint of AD and BC respectively then find the length of PQ . If AB=7cm and DC=17cm​

Answer 1

Answer:

$\large\implies\sf{PQ=12}$

Answer:

hence, PQ is mid point.

Formula to find the mid point is :

$\implies\sf\dfrac{1}{2}(ab + dc)$

so, PQ is,

$\implies\sf{PQ=\dfrac{1}{2}(ab +dc)}$

$\implies\sf{PQ=\dfrac{1}{2}(7+17)}$

$\implies\sf{PQ=\dfrac{1}{ \cancel2}( \cancel{24})}$

$\implies\sf{PQ={1}(12)}$

$\implies \boxed{\sf{PQ=12}}$