Question

ABCD is a trapezium and Ablled.
If AB= 20 cm , BC = 8 cm , CD = 10 cm and
AD= 6cm , then area of ABCD ist
10cm
8cm
6cm
20cm​

Answer 1

Answer:

answer is 8

Step-by-step explanation:

please,tell me my answer is right or wrong

Answer 2

ABCD is a trapezium and labelled. If, AB= 20 cm , BC = 8 cm , CD = 10 cm and

AD= 6cm. To find the area of ABCD :

• To answer this question we first draw a line DE parallel to CB.
• Now we have a triangle ADE, where AE=10cm and DE=8cm.
• Using Heron's Formula we can find the area of this triangle as follows :

A = √(s(s-a)(s-b)(s-c))

where s = (a+b+c)/2

• So, we find the area of this triangle using the above formula as ADE as 24 cm sq.
• Now, using the formula of triangle of ADE as = 1/2(base x height) = 24 cm sq, we can find the height of the triangle taking base as AE=10cm.
• Calculating the question we get, height = 4.8cm.

Now we know that the area of trapezium as = (a+b)h/2, where a and b are length of parallel sides of trapezium and h is the height.

Using the formula we get,

area of trapezium = ((10+20) x 4.8) / 2 = 72 cm sq.

Hence the area of the trapezium is 72 cm sq.