Question

ABCD is a trapezium and CDEF is a parallelogram. Find the shaded area.​

Answer 1

Area of shaded region = area of trapezium - area of ||gm + area of ∆

$area \: of \: parallelogram = base \: \times height \\ = 14 \times 6 \\ = 84 {cm}^{2} \\ \\ area \: of \: triangle = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 6 \times 8 \\ = 24 {cm}^{2} \\ \\ area \: of \: trapezium = \frac{1}{2} (a + b)h \\ = \frac{1}{2} (24 + 15)8 \\ = 39 \times 4 \\ = 156 {cm}^{2}$

$area \: of \: shaded \: region = \\ area \: of \: trapezium - area \\ \: of \: || gm \: + area \: of \: triangle \\ = 156 - 84 + 24 \\ = 156 - 108 \\ = 48cm²$