Question

ABCD is a trapezium AO:OC = 2:3 , if AB = 5cm find DC

Answer 1

Step-by-step explanation:

There form two ∆AOB and COD in trapezium

In ΔAOB and ΔCOD,

∠ AOB = ∠COD (Vertically opposite angles)

AO/OC = DO/OB (Given)

Therefore according to SAS similarity criterion,

ΔAOB ~ ΔCOD

AO/OC = BO/OD = AB/DC [corresponding sides of similar triangles are proportional]

⇒ 2/3= 5/DC

⇒ DC = 15/2

Hope this will help you :)