ABCD is a trapezium if AB ll CD angle a = 74 degree and Angle B : angle C =4:5. find the measure of angles D,B and C
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in trapezium angle A=angle B
so angle B=74
now angle C=(74*5)/4=92.50
now angle D=360-(74+74+92.5)=119.50
so B=74, D=119.50, C=92.50
so angle B=74
now angle C=(74*5)/4=92.50
now angle D=360-(74+74+92.5)=119.50
so B=74, D=119.50, C=92.50
YashPuri07:
you didn't write angle A = angle B
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this is the solution
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