Question

Abcd is a trapezium in which ab=5cm ad=bc=4cm and distance between the parallel sides AB and CD is 3cm find DC and area of trapezium abcd

Answer 1

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Answer 2

CD = 5 ± 2√7 , Area = 3(5 ± √7)  cm²  ab=5cm ad=bc=4cm and distance between the parallel sides AB and CD is 3cm find DC

Step-by-step explanation:

AD = BC = 4 cm (isosceles trap ezium)

AB = 5 cm

CD = AB ± 2 * √(4² - 3²)

CD = 5 ± 2√7

Area = (1/2) (5 + 5 ± 2√7) * 3

= 3(5 ± √7)  cm²

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