ABCD is a trapezium in which AB=7cm;AD=BC=5cm DC=x cm & distance between AB & DC is 4cm find the value of x
Answers
Hey dear here is your answer!!!!!
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To start off with, we have to draw perpendiculars from A and B on CD at E and F respectively.
Now, we will obtain two right-angled triangles.
We apply Pythagoras Theorem in both of them:-
DE² = AD² - AE²
DE² = 5² - 4²
DE² = 25 - 16
DE² = 9
DE = √9
DE = 3 cm
Similarly, FC = 3 cm
DC can be re-written as:-
=DE + EF + FC (Also, EF = AB as ABEF forms a rectangle)
=3 + 7 + 3
= 13cm
So, the value of x is 13cm !
❣️⭐ Hope it helps you dear...⭐⭐❣️❣️
Answer:
13 cm
Explanation :
DE² = AD² - AE²
DE² = 5² - 4²
DE² = 25 - 16
DE² = 9
DE = √9
DE = 3 cm
Similarly, FC = 3 cm
DC can be re-written as:-
=DE + EF + FC (Also, EF = AB as ABEF forms a rectangle)
=3 + 7 + 3
= 13cm
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