ABCD is a trapezium in which AB || CD, DE 1 AB. If AB + CD = (m + n) units and area is (m2-n2) sq. units, then length of DE is (a)2 (m+n) (b) 2 (m2-na) (c)2(m-n) (d) 2(m2 + n)
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Step-by-step explanation:
Given AB=12cm , MN=14cm
Since ,segment joining the mid-point of non-parallel sides of trapezium is half the sum of the lengths of its parallel sides.
⇒MN=21(AB+DC)
14=21(12+CD)
CD=28−12
CD=16cm
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