Question

ABCD is a trapezium in which AB || DC, AB = 3 CD and
Ar(AAOB)=108 cm². Ar(ACOD) is

A) 24 cm²

C) 48 cm²

B) 18 cm²

D) 12 cm²​

Answer 1

Answer:

12

Step-by-step explanation:

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Answer 2

Answer:

ABCD is a trapezium.

In which diagonal AC and BD intersect each other at O.

OB = OD

AO = OC

(1)To prove :- Triangle AOB and COD are similar.

angle AOB = DOC. [vertically opposite angle].

Side AB = CD.

Angle OAB = OCD. [ Each equal to 90°]

BY similarity criteria ASA

Triangle AOB similar to Triangle COD.

(2) OA= 6cm

and OC = 8cm

Let the base be X cm

Therefore,

Area of Triangle AOB/ Area of triangle COD = 1/2×X×6/1/2×Xm × 8.

Ar(AOB)/Ar(COD)= 6/8= 3/4