Question

ABCD is a trapezium in which AB || DC, AB =3CD and area(∆AOB) = 108 cm, then what is the area(∆COD) ​

Answer 1

Answer:

answer must be 18

Step-by-step explanation:

We know that the arc of similar triangles are proportional to squares of there corresponding altitudes, therefore with

(triangle AOB)=108 cm square and AB=3cd

we have

(triangle AOB)/(triangle COD=AB square/CD square

108/triangle cod=6cd square/cd square

108/triangle COD=6

Triangle COD=108/6

triangle COD =18