Question

ABCD is a trapezium in which AB// DC, AB is 16 cm and DC is 24 cm. If the area of the trapezium is

215 cm2
, find the distance between its parallel sides

Let me know fast pls❤✨​

Answer 1

Answer:

10.75 cm

Step-by-step explanation:

Area of trapezium = 1/2 X (sum of parallel sides) X distance between it's parallel sides

215 = 1/2 X (24+16) X h

215 = 1/2 X 40 X h

215 = 20h

215/20 = h

h = 10.75 cm

so the distance between it's parallel sides = 10.75 cm

Answer 2

$area \: of \: trapizium = \frac{h(a + b)}{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 215 \: {cm}^{2} = \frac{h(16 + 24) }{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 215 = \frac{h \times 40}{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 215 = h \times 20$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{215}{20} = h$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 10.75 = h$

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