Question

ABCD is a trapezium in which AB|DC and angle A = 55 degree. iF Ao and Do are the angle bisectors meets at 0.Find the measure of angle AOD.​

Answer 1

Answer:

∠AOB=90°

Step-by-step explanation:

ABCD is a parallelogram

⇒ ∠A+∠B=180

o

[ Sum of adjacent angles of parallelogram are supplementary ]

⇒ 21

∠A+ 21 ∠B= 2

180°

⇒ ∠OAB+∠OBA=90°

In △AOB

⇒ ∠OAB+∠AOB+∠OBA=180 °

⇒ ∠AOB=180 ° −(∠OAB+∠OBA)

⇒ ∠AOB=180 °−(∠OAB+∠OBA)

⇒ ∠AOB=180°

−90°

∴ ∠AOB=90°

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