ABCD is a trapezium in which AB || DC and angle A= angle B = 55°. Find angle C and angle D
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Answered by
6
let's proceed to this question : -
as we know that the opposite angles of a parallelogram is equal the the sum of the other two angles will be also the same
the angle sum property of a quadrilateral is 360°
the sum of the two angles is 55+55= 110 °
so the sum of the another two angle is 360°- 110°/2 = 250°/2 = 175°
the other two angles are of 175°
as we know that the opposite angles of a parallelogram is equal the the sum of the other two angles will be also the same
the angle sum property of a quadrilateral is 360°
the sum of the two angles is 55+55= 110 °
so the sum of the another two angle is 360°- 110°/2 = 250°/2 = 175°
the other two angles are of 175°
Answered by
11
AB II DC and BC is the transversal,
55°+ <C = 180°( sum of co interior angles =180)
<C = 180-55
<C = 125°
AB II DC and AD is the transversal,
55° + <D = 180°(sum of co interior angles =180)
<D = 180- 55
<D = 125°
hope it helps u..
55°+ <C = 180°( sum of co interior angles =180)
<C = 180-55
<C = 125°
AB II DC and AD is the transversal,
55° + <D = 180°(sum of co interior angles =180)
<D = 180- 55
<D = 125°
hope it helps u..
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