ABCD is a trapezium in which AB|| DC and its diagonal intersect at O point. show AB divide by BO and CO divide by DO
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Given:-ABCD is a trapezium, AB II DC
To Prove:- AO/BO = CO/DO or by alterando AO/CO = BO/DO
Construction:-EF II DC
Proof:- In ▲ACD , OE II CD
AE/ED = AO/OC (By BPT)......(1)
In ▲ABD , DC II EF II AB OR EF II AB
AE/ED = BO/DO (By BPT)........(2)
By (1) and (2), we get
AO/CO = BO/DO
Hence proved
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