Question

ABCD is a trapezium in which AB||DC and its diagonals intersect each other at the point O .Show that AO/BO=CO/DO​

Answer 1

Answer:

AB||CD

in triangle AOB & triangle COD

angle AOB= angle COD [vertically opp. angle]

angle OAB= angle OCD [alternate interior angles]

where AA is similarity then,

tri AOB~tri COD

AO/BO=CO/DO [where triangles are similar]

Answer 2

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