ABCD is a trapezium in which AB // DC and its diagonals intersect each other at the point O. Show that AO/BO = CO/DO
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Answer:
Step-by-step explanation:
ABCD is a trapezium where AB || DC and diagonals AC and BD intersect at O.
To prove
AOBO=CODO
Construction
Draw a line EF passing through O and also parallel to AB
Now, AB ll CD
By construction EF ll AB
∴ EF ll CD
Consider the ΔADC,
Where EO ll AB
According to the basic proportionality theorem
AEED=AOOC ………………………………(1)
Now consider Δ ABD
where EO ll AB
According to the basic proportionality theorem
DE/EA = DO/BO…………….(ii)
From equation (i) and (ii), we get,
AO/CO = BO/DO
⇒AO/BO = CO/DO
Hence, proved.
Hence the proof.
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