Question

ABCD is a trapezium in which AB|| DC and P, Q are points on AD and BC respectively such that PQ
II DC. If PD = 18 cm, BQ = 35 cm and QC = 15 cm, find AD.
(4)​

Answer 1

Answer:

AD =60  cm

Step-by-step explanation:

A megoldásom itt van:

AED Δ ≈ PFD Δ

AD : PD = ED : DF \\

AD = \frac{ED \cdot PD}{DF}  = \frac{(15+35) \cdot 18}{15} = 60 cm \\