ABCD is a trapezium in which AB//DC , BD is a diagonal & E is the mid point of AD .A line is drawn through E parallel to AB intersecting BC at F.Show that F is the mid point of BC.
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ABCD is a trapezium in which AB || DC, BD is a
diagonal and E is the mid-point of AD and a line is drawn through E parallel to
AB intersecting BC at F such that EF||AB.
To Show:
F is the mid-point of BC.
Proof:
Let EF intersected BD at G.
In ΔABD,
E is the mid point of AD and also EG || AB.
we get, G is the mid point of BD
(by Converse of mid-point theorem)
Similarly,
In ΔBDC,
G is the mid point of BD and GF || AB || DC.
Thus, F is the mid point of BC
(by Converse of mid point theorem)
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