ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point
of AD. A line is drawn through E parallel to AB intersecting BC at F. Show that
F is the mid-point of BC.
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Answers
Trapezium:
A quadrilateral in
which one pair of opposite sides are parallel is called a trapezium.
Converse
of mid point theorem:
The
line drawn through the midpoint of one side of a triangle, parallel to another
side bisect the third side.
========================================================
Given,
ABCD is a trapezium in which AB || DC, BD is a
diagonal and E is the mid-point of AD and a line is drawn through E parallel to
AB intersecting BC at F such that EF||AB.
To Show:
F is the mid-point of BC.
Proof:
Let EF
intersected BD at G.
In ΔABD,
E is the mid point of AD and also EG || AB.
we get, G is the mid point of BD
(by Converse of mid
point theorem)
Similarly,
In ΔBDC,
G is the mid point of BD and GF || AB || DC.
Thus, F is the mid point of BC
(by Converse of mid point theorem)
_____________________________________________________________
Hope this will help you...
Answer:
Trapezium:
A quadrilateral in which one pair of opposite sides are parallel is called a trapezium.
Converse of mid point theorem:
The line drawn through the midpoint of one side of a triangle, parallel to another side bisect the third side.
========================================================
Given,
ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD and a line is drawn through E parallel to AB intersecting BC at F such that EF||AB.
To Show:
F is the mid-point of BC.
Proof:
Let EF intersected BD at G.
In ΔABD,
E is the mid point of AD and also EG || AB.
we get, G is the mid point of BD
(by Converse of mid point theorem)
Similarly,
In ΔBDC,
G is the mid point of BD and GF || AB || DC.
Thus, F is the mid point of BC
(by Converse of mid point theorem)
_____________________________________________________________
Hope this will help you...
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