Question

ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn
through E parallel to AB intersecting BC at F (see Fig). Show that F is the mid-point of BC.
pls answer it's urgent !!!!!​

Answer 1

Answer:

Here is your answer... Hope it helps you.

Answer 2

Answer:

Given, ABCD is a trapezium

Step-by-step explanation:

We have to prove, F is the mid point of BC.

i.e., BF=CF

Let, EF intersect DB at G.

In ∆ABD, E is the mid point of AD and EG||AB.

Therefore, G will be the mid point of DB.

Now, EF||AB and AB||CD

So, EF||CD

Therefore, In ∆BCD,

GF||CD

Hence, it is proved that F is the mid point of BC.