ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD
A line is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30). Show that
F is the mid point of BC.
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Answer:
Step-by-step explanation:
Solution:
Given that,
ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD.
To prove,
F is the mid-point of BC.
Proof,
BD intersected EF at G.
In ΔBAD,
E is the mid point of AD and also EG || AB.
Thus, G is the mid point of BD (Converse of mid point theorem)
Now,
In ΔBDC,
G is the mid point of BD and also GF || AB || DC.
Thus, F is the mid point of BC (Converse of mid point theorem)
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