Question

ABCD is a trapezium in which AB ||DC.if/A=/B =30°,what are the measure of the other two angles

Answer 1

Given- A=B= 30°
let,C and D = x°

sum of all angles of a trapezium = 360°
A +B+C+D = 360°
30° +30°+ X +X = 360°
60° + 2x = 360°
2x = 360° -60°
2x = 300°
x = 300/2
x = 150°
so, C And D = 150°

Answer 2

Answer:

sum of all angles of a trapezium = 360°

A +B+C+D = 360°

30° +30°+ X +X = 360°

60° + 2x = 360°

2x = 360° -60°

2x = 300°

x = 300/2

x = 150°