Question

ABCD is a trapezium in which AB//DC. If angle A = 55 desgree and angle B = 70 degree find angle C and angle D

Answer 1

AB || DC we have
<A + <D = 180°
55°+ <D = 180°
<D = 180°-55°
= 125°
also,
<B + <C = 180°
70° + <C = 180 °
<C = 180°-70°
= 110°

Answer 2

∠ C = 110° and ∠ D = 125°

Step-by-step explanation:

Given that,

In the trapezium ABCD,

AB ║ DC

∠A = 55°

∠ B = 70°

As we know,

∠A + ∠D = 180°                              (∵ consecutive interior angles)

So,

∠D = 180° - ∠A

= 180° - 55°

= 125°

∵ ∠D = 125°

Now, we know that sum of all the four angles of quadrilateral is 360°

So,

∠ A + ∠ B + ∠ C + ∠ D = 360°            (∵ sum of angles of quadrilateral = 360°)

by putting the values of ∠A, ∠B, and ∠D, we cand the value of ∠C

⇒ 55° + 70° + ∠C + 125° = 360°

⇒ ∠C = 360° - (55° + 70°+ 125°)

⇒ ∠C = 360° - 250°

∵ ∠C = 110°

Thus, the value of ∠C is 110° and the value of ∠D is 125°

Learn more: find the angle

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