Question

ABCD is a trapezium in which AB॥DC . if angle a =angle b=40, What are the measure of the other two angles?​

Answer 1

Answer:

140 degree each

Step-by-step explanation:

Let the other two angles be x.

⇒Sum of all angles = 360 degree

angle A + B + C + D = 360 degree

40 degree + 40 degree + angle C + D = 360 degree

80 degree + angle C + D = 360 degree

angle C + D = 360 - 80 degree

x + x = 280 degree

2x = 280 degree

x = 280/2 degree

⇒x = 140 degree

Hence the measure of the other two angles is 140 degree each.

Hope it helps.

Please mark this answer as BRAINLIEST.

Answer 2

Answer:

here the base angles are equal so quadrilateral abcd is isoscele trapezium in which angle a= angle b

let us assume that another angle be x

angle a + angle b + angle c+ angle d= 360

x+x+40+40=360

2x+80=360

2x=280

x=140

angle d= angle c= 140 degree