Question

ABCD is a trapezium in which AB//DC .If<A=<B=40, find the measures of other two angles
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Answer 1

Answer :-

• The two other angles are 140° and 140°.

Given :-

• ABCD is a trapezium in which AB || DC and ∠A = ∠B = 40°.

To Find :-

• Measure of the other two angles.

Solution :-

Here

• ∠A = 40°
• ∠B = 40°

→ It's an isosceles trapezium.

Let

• ∠C = ∠D = x

As we know that

→ Sum of all angles of a quadrilateral is 360°.

According to question :-

⇒ 40 + 40 + x + x = 360

⇒ 80 + x + x = 360

⇒ 80 + 2x = 360

⇒ 2x = 360 - 80

⇒ 2x = 280

⇒ x = 280/2

⇒ x = 140

Now

• ∠C = ∠D = x = 140°

Hence, the other two angles are 140° and 140°.