Question

ABCD is a trapezium in which AB II DC, BD is a diagonal and Eis the mid-point of AL
A line is drawn through E parallel to AB intersecting BC at F(see Fig. 8.30). Show they
Fis the mid-point of BC.

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Answer 1

Answer:

Given ABCD is a trapezium.

We have to prove, F is the mid point of BC, i.e., BF=CF

Let EF intersect DB at G.

In ΔABD E is the mid point of AD and EG∣∣AB.

∴ G will be the mid-point of DB.

Now EF∣∣AB and AB∣∣CD

∴ EF∣∣CD

∴ In ΔBCD, GF∣∣CD

⇒ F is the mid point of BC.

Answer 2

Answer:

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Step-by-step explanation:

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