Question

ABCD is a trapezium in which AB IIDC, Bo is a
diagonal and E is the mid point of AD. A line
line is drawn through & parallel to AB intersect-
BC at F. Show that t is the mid point of BC.​

Answer 1

Step-by-step explanation:

ABCD is a trapezium.

We have to prove, F is the mid point of BC, i.e., BF=CF

Let EF intersect DB at G.

In ΔABD E is the mid point of AD and EG∣∣AB.

∴ G will be the mid-point of DB.

Now EF∣∣AB and AB∣∣CD

∴ EF∣∣CD

∴ In ΔBCD, GF∣∣CD

⇒ F is the mid point of BC.

Answer 2

Answer:

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Step-by-step explanation:

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