Question

ABCD is a trapezium in which ab is parallel to CD and shown the area of the trapezium is

Answer 1

Heya mate!
Formula of area of trapezium is
$\frac{1}{2} \times height(sum \: of \: parallel \: sides)$
In this figure,
DC is 52 cm and AB is 78 cm, so the part of AB which is exactly below DC will also be 52 cm and its left and right side will be... 78-52=26 and half of 26 is 13, so AB is divided into 3 parts of 13cm, 52cm and 13cm.
Height of the trapezium will be....
According to Pythagoras theorem, hypotenuse^2 =base^2+ perpendicular^2
${28}^{2} is \: equal \: to \: {13}^{2} + {x}^{2}$
784=169+x^2
784-169=x^2
615=x^2
x=24.7
Height=24.7
=1/2×24.7(52+78)
=1605.5
Hope its correct and it helps you because it took lots of time and efforts to solve it...
Mark as brainliest please