Question

ABCD is a trapezium in which AB is parallel to CD . If angle A =140 find angle D

Answer 1

Answer:

Given a trapezium ABCD and AB is parallal to the side CD angle the measure of angle A is 140°

A/Q we. we'd to calculate out the value of the angle D

We know that the sum of consecutive angles of a Quadrilateral is 180°

So for finding the value of angle D we will do the sum of angle A and angle D and then we will show the summesion of angles is equal to 180 °

•°• angle A+ Angle D = 180

$= > 140 + angle \: d \: = 180 \degree \\ \\ = > angle \: d \: = 180 \degree- 140 \degree\\ \\ = > angle \: d = 40 \degree$

So from the above calculation we find the value of angle D is

$\huge{\red{40 \degree}}$

Answer 2

Answer:

40 degrees

this is my answer